Mathématiques

Question

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1 Réponse

  • Bonjour,


    a) a = - 1 ; b = 1/3 ; c = 2/5


    A = a/b + c

    A = - 1 : 1/3 + 2/5

    A = - 1 x 3/1 + 2/5

    A = - 3 + 2/5

    A = (- 3 x 5) / (1 x 5) + 2/5

    A = - 15/5 + 2/5

    A = - 13/5


    B = (a + b) / c

    B = (- 1 + 1/3) / 2/5

    B = [(- 1 x 3) / (1 x 3) + 1/3] : 2/5

    B = (- 3/3 + 1/3) : 2/5

    B = - 2/3 : 2/5

    B = - 2/3 x 5/2

    B = - 10/6

    B = - 5/3


    C = a / (b + c)

    C = - 1 / (1/3 + 2/5)

    C = - 1 : [[1 x 5) / (3 x 5) + (2 x 3) / (5 x 3)]

    C = - 1 : (5/15 + 6/15)

    C = - 1 : 11/15

    C = - 1 x 15/11

    C = - 15/11


    b) a = 1/2 ; b = - 5/4 ; c = 3/4

    B = (a + b) / c

    B = (1/2 - 5/4) : 3/4

    B = [(1 x 2) / (2 x 2) - 5/4] : 3/4

    B = (2/4 - 5/4) : 3/4

    B = - 3/4 : 3/4

    B = - 3/4 x 4/3

    B = - 12/12

    B = - 1


    C = a / (b + c)

    C = 1/2 : (- 5/4 + 3/4)

    C = 1/2 : (- 2/4)

    C = 1/2 x - 4/2

    C = - 4/4

    C = - 1

    Julia  a raison.

    C = a / (b + c)